((2x+5)/3)=x+2

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Solution for ((2x+5)/3)=x+2 equation: 



((2x+5)/3)=x+2

We move all terms to the left:

((2x+5)/3)-(x+2)=0

We get rid of parentheses

((2x+5)/3)-x-2=0

We multiply all the terms by the denominator


((2x+5)-x*3)-2*3)=0



We calculate terms in parentheses: +((2x+5)-x*3), so:

(2x+5)-x*3

Wy multiply elements

(2x+5)-3x

We get rid of parentheses

2x-3x+5

We add all the numbers together, and all the variables

-1x+5

Back to the equation:

+(-1x+5)



We add all the numbers together, and all the variables

(-1x+5)=0

We get rid of parentheses

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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