((2x+6)/4)+((3x-7)/2)=-18

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Solution for ((2x+6)/4)+((3x-7)/2)=-18 equation: 



((2x+6)/4)+((3x-7)/2)=-18

We move all terms to the left:

((2x+6)/4)+((3x-7)/2)-(-18)=0

We add all the numbers together, and all the variables

((2x+6)/4)+((3x-7)/2)+18=0

We calculate fractions


(4x+12)/()+(12x-28)/()+18=0

We multiply all the terms by the denominator


(4x+12)+(12x-28)+18*()=0

We add all the numbers together, and all the variables

(4x+12)+(12x-28)=0

We get rid of parentheses

4x+12x+12-28=0

We add all the numbers together, and all the variables

16x-16=0

We move all terms containing x to the left, all other terms to the right

16x=16

x=16/16

x=1

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