((2x+60)+(3x+10)=145)

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Solution for ((2x+60)+(3x+10)=145) equation: 



((2x+60)+(3x+10)=145)

We move all terms to the left:

((2x+60)+(3x+10)-(145))=0



We calculate terms in parentheses: +((2x+60)+(3x+10)-145), so:

(2x+60)+(3x+10)-145

We get rid of parentheses

2x+3x+60+10-145

We add all the numbers together, and all the variables

5x-75

Back to the equation:

+(5x-75)



We get rid of parentheses

5x-75=0

We move all terms containing x to the left, all other terms to the right

5x=75

x=75/5

x=15

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