((2x+60)+(3x+10)=180)

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Solution for ((2x+60)+(3x+10)=180) equation: 



((2x+60)+(3x+10)=180)

We move all terms to the left:

((2x+60)+(3x+10)-(180))=0



We calculate terms in parentheses: +((2x+60)+(3x+10)-180), so:

(2x+60)+(3x+10)-180

We get rid of parentheses

2x+3x+60+10-180

We add all the numbers together, and all the variables

5x-110

Back to the equation:

+(5x-110)



We get rid of parentheses

5x-110=0

We move all terms containing x to the left, all other terms to the right

5x=110

x=110/5

x=22

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