((2x+7)/21)=6-3/7x

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Solution for ((2x+7)/21)=6-3/7x equation: 



((2x+7)/21)=6-3/7x

We move all terms to the left:

((2x+7)/21)-(6-3/7x)=0



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

((2x+7)/21)-(-3/7x+6)=0

We get rid of parentheses

((2x+7)/21)+3/7x-6=0

We calculate fractions


(((2x+7)*7x)/21*7x)+()/21*7x)-6=0



We calculate terms in parentheses: +(((2x+7)*7x)/21*7x), so:

((2x+7)*7x)/21*7x

We multiply all the terms by the denominator


((2x+7)*7x)



We calculate terms in parentheses: +((2x+7)*7x), so:

(2x+7)*7x

We multiply parentheses

14x^2+49x

Back to the equation:

+(14x^2+49x)



We get rid of parentheses

14x^2+49x

Back to the equation:

+(14x^2+49x)



We get rid of parentheses

14x^2+49x+()/21*7x)-6=0

We multiply all the terms by the denominator


14x^2*21*7x)-6+49x*21*7x)-6+()=0

Wy multiply elements

302526x^4*7=0

We do not support expression: x^4

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