((2x+8)/6)+8=x-4

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Solution for ((2x+8)/6)+8=x-4 equation: 



((2x+8)/6)+8=x-4

We move all terms to the left:

((2x+8)/6)+8-(x-4)=0

We get rid of parentheses

((2x+8)/6)-x+4+8=0

We multiply all the terms by the denominator


((2x+8)-x*6)+4*6)+8*6)=0



We calculate terms in parentheses: +((2x+8)-x*6), so:

(2x+8)-x*6

Wy multiply elements

(2x+8)-6x

We get rid of parentheses

2x-6x+8

We add all the numbers together, and all the variables

-4x+8

Back to the equation:

+(-4x+8)



We add all the numbers together, and all the variables

(-4x+8)=0

We get rid of parentheses

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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