((2x-1)/3)+((3x+4)/4)=(7(x-3))/10

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Solution for ((2x-1)/3)+((3x+4)/4)=(7(x-3))/10 equation: 


x in (-oo:+oo)

(2*x-1)/3+(3*x+4)/4 = (7*(x-3))/10 // - (7*(x-3))/10

(2*x-1)/3+(3*x+4)/4-((7*(x-3))/10) = 0

(2*x-1)/3+(3*x+4)/4+(-7/10)*(x-3) = 0

(2*x-1)/3+(3*x+4)/4-7/10*(x-3) = 0

(4*(2*x-1))/(3*4)+(3*(3*x+4))/(3*4)+(-7/10*3*4*(x-3))/(3*4) = 0

4*(2*x-1)+3*(3*x+4)-7/10*3*4*(x-3) = 0

17*x-42/5*x+8+126/5 = 0

43/5*x+166/5 = 0

(43/5*x+166/5)/(3*4) = 0

(43/5*x+166/5)/(3*4) = 0 // * 3*4

43/5*x+166/5 = 0

43/5*x+166/5 = 0 // - 166/5

43/5*x = -166/5 // : 43/5

x = -166/5/43/5

x = -166/43

x = -166/43

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