((2x-1)/6)+((3x+6)/8)=((1-4x)/12)

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Solution for ((2x-1)/6)+((3x+6)/8)=((1-4x)/12) equation:


x in (-oo:+oo)

(2*x-1)/6+(3*x+6)/8 = (1-(4*x))/12 // - (1-(4*x))/12

(2*x-1)/6+(3*x+6)/8-((1-(4*x))/12) = 0

(2*x-1)/6+(3*x+6)/8-((1-4*x)/12) = 0

(2*x-1)/6+(3*x+6)/8+(-1*(1-4*x))/12 = 0

(8*12*(2*x-1))/(6*8*12)+(6*12*(3*x+6))/(6*8*12)+(-1*6*8*(1-4*x))/(6*8*12) = 0

8*12*(2*x-1)+6*12*(3*x+6)-1*6*8*(1-4*x) = 0

408*x+192*x-48+336 = 0

600*x+288 = 0

(600*x+288)/(6*8*12) = 0

(600*x+288)/(6*8*12) = 0 // * 6*8*12

600*x+288 = 0

600*x+288 = 0 // - 288

600*x = -288 // : 600

x = -288/600

x = -12/25

x = -12/25

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