((2x-3)/(3x+7))+((6)/(4x-1))

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Solution for ((2x-3)/(3x+7))+((6)/(4x-1)) equation: 


D( x )

4*x-1 = 0

3*x+7 = 0

4*x-1 = 0

4*x-1 = 0

4*x-1 = 0 // + 1

4*x = 1 // : 4

x = 1/4

3*x+7 = 0

3*x+7 = 0

3*x+7 = 0 // - 7

3*x = -7 // : 3

x = -7/3

x in (-oo:-7/3) U (-7/3:1/4) U (1/4:+oo)

(2*x-3)/(3*x+7)+6/(4*x-1) = 0

((2*x-3)*(4*x-1))/((3*x+7)*(4*x-1))+(6*(3*x+7))/((3*x+7)*(4*x-1)) = 0

(2*x-3)*(4*x-1)+6*(3*x+7) = 0

8*x^2+4*x+45 = 0

8*x^2+4*x+45 = 0

8*x^2+4*x+45 = 0

DELTA = 4^2-(4*8*45)

DELTA = -1424

DELTA < 0

1 = 0

1/((3*x+7)*(4*x-1)) = 0

1/((3*x+7)*(4*x-1)) = 0 // * (3*x+7)*(4*x-1)

1 = 0

x belongs to the empty set

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