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((2x-3)/(x+2))-2=0
Domain of the equation: (x+2))!=0We multiply all the terms by the denominator
x∈R
((2x-3)-2*(x+2))=0
We calculate terms in parentheses: +((2x-3)-2*(x+2)), so:We add all the numbers together, and all the variables
(2x-3)-2*(x+2)
We multiply parentheses
(2x-3)-2x-4
We get rid of parentheses
2x-2x-3-4
We add all the numbers together, and all the variables
-7
Back to the equation:
+(-7)
-7!=0
There is no solution for this equation
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