((2x-3)/3)+((3x-10)/2)=20

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Solution for ((2x-3)/3)+((3x-10)/2)=20 equation: 



((2x-3)/3)+((3x-10)/2)=20

We move all terms to the left:

((2x-3)/3)+((3x-10)/2)-(20)=0

We calculate fractions


(4x-6)/()+(9x-30)/()-20=0

We multiply all the terms by the denominator


(4x-6)+(9x-30)-20*()=0

We add all the numbers together, and all the variables

(4x-6)+(9x-30)=0

We get rid of parentheses

4x+9x-6-30=0

We add all the numbers together, and all the variables

13x-36=0

We move all terms containing x to the left, all other terms to the right

13x=36

x=36/13

x=2+10/13

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