((2x-3)/4)+(5)=3x)

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Solution for ((2x-3)/4)+(5)=3x) equation: 



((2x-3)/4)+(5)=3x)

We move all terms to the left:

((2x-3)/4)+(5)-(3x))=0

We multiply all the terms by the denominator


((2x-3)-3x+5)*4)=0



We calculate terms in parentheses: +((2x-3)-3x+5)*4), so:

(2x-3)-3x+5)*4

We add all the numbers together, and all the variables

-3x+(2x-3)

We get rid of parentheses

-3x+2x-3

We add all the numbers together, and all the variables

-1x-3

Back to the equation:

+(-1x-3)



We get rid of parentheses

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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