((2x-3)/4)+20=3x

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Solution for ((2x-3)/4)+20=3x equation: 


x in (-oo:+oo)

(2*x-3)/4+20 = 3*x // - 3*x

(2*x-3)/4-(3*x)+20 = 0

(2*x-3)/4-3*x+20 = 0

(2*x-3)/4+(-3*4*x)/4+(4*20)/4 = 0

2*x-3*4*x+4*20-3 = 0

80-10*x-3 = 0

77-10*x = 0

(77-10*x)/4 = 0

(77-10*x)/4 = 0 // * 4

77-10*x = 0

77-10*x = 0 // - 77

-10*x = -77 // : -10

x = -77/(-10)

x = 77/10

x = 77/10

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