((2x-3)/5)-((x-2)/10)=((2x+1)/2)-x

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Solution for ((2x-3)/5)-((x-2)/10)=((2x+1)/2)-x equation: 


x in (-oo:+oo)

(2*x-3)/5-((x-2)/10) = (2*x+1)/2-x // - (2*x+1)/2-x

(2*x-3)/5-((x-2)/10)-((2*x+1)/2)+x = 0

(2*x-3)/5+(-1*(x-2))/10+(-1*(2*x+1))/2+x = 0

(2*10*(2*x-3))/(2*5*10)+(-1*2*5*(x-2))/(2*5*10)+(-1*5*10*(2*x+1))/(2*5*10)+(2*5*10*x)/(2*5*10) = 0

2*10*(2*x-3)-1*2*5*(x-2)-1*5*10*(2*x+1)+2*5*10*x = 0

30*x-100*x+100*x-50-40 = 0

100*x-70*x-90 = 0

30*x-90 = 0

(30*x-90)/(2*5*10) = 0

(30*x-90)/(2*5*10) = 0 // * 2*5*10

30*x-90 = 0

30*x-90 = 0 // + 90

30*x = 90 // : 30

x = 90/30

x = 3

x = 3

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