((2x-3)/6)-(7/2)=(5x-2)/3

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Solution for ((2x-3)/6)-(7/2)=(5x-2)/3 equation: 


x in (-oo:+oo)

(2*x-3)/6-(7/2) = (5*x-2)/3 // - (5*x-2)/3

(2*x-3)/6-((5*x-2)/3)-(7/2) = 0

(2*x-3)/6-((5*x-2)/3)-7/2 = 0

(2*x-3)/6+(-1*(5*x-2))/3-7/2 = 0

(2*3*(2*x-3))/(2*3*6)+(-1*2*6*(5*x-2))/(2*3*6)+(-7*3*6)/(2*3*6) = 0

2*3*(2*x-3)-1*2*6*(5*x-2)-7*3*6 = 0

6-48*x-126 = 0

-48*x-120 = 0

(-48*x-120)/(2*3*6) = 0

(-48*x-120)/(2*3*6) = 0 // * 2*3*6

-48*x-120 = 0

-48*x-120 = 0 // + 120

-48*x = 120 // : -48

x = 120/(-48)

x = -5/2

x = -5/2

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