((2x-5)(x+3))/(x-2)=0

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Solution for ((2x-5)(x+3))/(x-2)=0 equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

((2*x-5)*(x+3))/(x-2) = 0

( 2*x-5 )

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

( x+3 )

x+3 = 0 // - 3

x = -3

x in { 5/2, -3 }

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