((2x-5)/7)+x=3

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Solution for ((2x-5)/7)+x=3 equation: 



((2x-5)/7)+x=3

We move all terms to the left:

((2x-5)/7)+x-(3)=0

We add all the numbers together, and all the variables

x+((2x-5)/7)-3=0

We multiply all the terms by the denominator


x*7)+((2x-5)-3*7)=0

We add all the numbers together, and all the variables

x*7)+((2x-5)=0

Wy multiply elements

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$

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