((2y-3)/4)+((y-4)/3)=1

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Solution for ((2y-3)/4)+((y-4)/3)=1 equation: 



((2y-3)/4)+((y-4)/3)=1

We move all terms to the left:

((2y-3)/4)+((y-4)/3)-(1)=0

We calculate fractions


(6y-9)/()+(4y-16)/()-1=0

We multiply all the terms by the denominator


(6y-9)+(4y-16)-1*()=0

We add all the numbers together, and all the variables

(6y-9)+(4y-16)=0

We get rid of parentheses

6y+4y-9-16=0

We add all the numbers together, and all the variables

10y-25=0

We move all terms containing y to the left, all other terms to the right

10y=25

y=25/10

y=2+1/2

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