((2z+7)/8)-2=z+((z-1)/2)

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Solution for ((2z+7)/8)-2=z+((z-1)/2) equation: 


z in (-oo:+oo)

(2*z+7)/8-2 = (z-1)/2+z // - (z-1)/2+z

(2*z+7)/8-((z-1)/2)-z-2 = 0

(2*z+7)/8+(-1*(z-1))/2-z-2 = 0

(2*(2*z+7))/(2*8)+(-1*8*(z-1))/(2*8)+(2*8*(-z))/(2*8)+(-2*2*8)/(2*8) = 0

2*(2*z+7)-1*8*(z-1)+2*8*(-z)-2*2*8 = 0

22-4*z-16*z-32 = 0

22-20*z-32 = 0

-20*z-10 = 0

(-20*z-10)/(2*8) = 0

(-20*z-10)/(2*8) = 0 // * 2*8

-20*z-10 = 0

-20*z-10 = 0 // + 10

-20*z = 10 // : -20

z = 10/(-20)

z = -1/2

z = -1/2

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