((2z-16)/(121))/((z-8)/(22))

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Solution for ((2z-16)/(121))/((z-8)/(22)) equation:


D( z )

(z-8)/22 = 0

(z-8)/22 = 0

(z-8)/22 = 0

z-8 = 0 // + 8

z = 8

z in (-oo:8) U (8:+oo)

((2*z-16)/121)/((z-8)/22) = 0

(22*(2*z-16))/(121*(z-8)) = 0

2*z-16 = 0 // + 16

2*z = 16 // : 2

z = 16/2

z = 8

z in { 8}

z belongs to the empty set

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