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((2z-3)/5)-((z-6)/4)=3
We move all terms to the left:
((2z-3)/5)-((z-6)/4)-(3)=0
We calculate fractions
(8z-12)/()+(-5z+30)/()-3=0
We multiply all the terms by the denominator
(8z-12)+(-5z+30)-3*()=0
We add all the numbers together, and all the variables
(8z-12)+(-5z+30)=0
We get rid of parentheses
8z-5z-12+30=0
We add all the numbers together, and all the variables
3z+18=0
We move all terms containing z to the left, all other terms to the right
3z=-18
z=-18/3
z=-6
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