((3+1)/m)=2

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Solution for ((3+1)/m)=2 equation: 



((3+1)/m)=2

We move all terms to the left:

((3+1)/m)-(2)=0



Domain of the equation: m)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

(4/m)-2=0

We get rid of parentheses

4/m-2=0

We multiply all the terms by the denominator


-2*m+4=0

We add all the numbers together, and all the variables

-2m+4=0

We move all terms containing m to the left, all other terms to the right

-2m=-4

m=-4/-2

m=+2

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