((3-4x)/6)-((2x-3)/8)=2-x

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Solution for ((3-4x)/6)-((2x-3)/8)=2-x equation: 



((3-4x)/6)-((2x-3)/8)=2-x

We move all terms to the left:

((3-4x)/6)-((2x-3)/8)-(2-x)=0

We add all the numbers together, and all the variables

((-4x+3)/6)-((2x-3)/8)-(-1x+2)=0

We get rid of parentheses

((-4x+3)/6)-((2x-3)/8)+1x-2=0

We calculate fractions


1x+(-32x+24)/()+(-12x+18)/()-2=0

We add all the numbers together, and all the variables

x+(-32x+24)/()+(-12x+18)/()-2=0

We multiply all the terms by the denominator


x*()+(-32x+24)+(-12x+18)-2*()=0

We add all the numbers together, and all the variables

x*()+(-32x+24)+(-12x+18)=0

We get rid of parentheses

x*()-32x-12x+24+18=0

We add all the numbers together, and all the variables

-44x+x*()+42=0

We move all terms containing x to the left, all other terms to the right

-44x+x*()=-42

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