((3/2)/(6/4))=(18/n)

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Solution for ((3/2)/(6/4))=(18/n) equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

(3/2)/(6/4) = 18/n // - 18/n

(3/2)/(6/4)-(18/n) = 0

(3/2)/(6/4)-18*n^-1 = 0

-18*n^-1 = -1 // : -18

n^-1 = 1/18

-1 < 0

1/(n^1) = 1/18 // * n^1

1 = 1/18*n^1 // : 1/18

18 = n^1

n = 18

n = 18

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