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((3/2)n)-(8/3)=-29/12
We move all terms to the left:
((3/2)n)-(8/3)-(-29/12)=0
Domain of the equation: 2)n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
((+3/2)n)-(+8/3)-(-29/12)=0
We get rid of parentheses
((+3/2)n)-8/3+29/12=0
We calculate fractions
()/2n)*3*12)+(-192n)/2n)*3*12)+174n/2n)*3*12)=0
We can not solve this equation
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