((3/2x)(3))-12=18

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Solution for ((3/2x)(3))-12=18 equation: 



((3/2x)(3))-12=18

We move all terms to the left:

((3/2x)(3))-12-(18)=0



Domain of the equation: 2x)3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

((+3/2x)3)-12-18=0

We add all the numbers together, and all the variables

((+3/2x)3)-30=0

We multiply all the terms by the denominator


((+3-30*2x)3)=0



We calculate terms in parentheses: +((+3-30*2x)3), so:

(+3-30*2x)3

We add all the numbers together, and all the variables

(-30*2x+3)3

We multiply parentheses

-180x+9

Back to the equation:

+(-180x+9)



We get rid of parentheses

-180x+9=0

We move all terms containing x to the left, all other terms to the right

-180x=-9

x=-9/-180

x=1/20

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