((300+b)/300)=300/b

Solution for ((300+b)/300)=300/b equation:

((300+b)/300)=300/b

We move all terms to the left:

((300+b)/300)-(300/b)=0


Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

((b+300)/300)-(+300/b)=0

We get rid of parentheses

((b+300)/300)-300/b=0

We calculate fractions


(((b+300)*b)/300*b)+()/300*b)=0


We calculate terms in parentheses: +(((b+300)*b)/300*b), so:

((b+300)*b)/300*b

We multiply all the terms by the denominator


((b+300)*b)


We calculate terms in parentheses: +((b+300)*b), so:

(b+300)*b

We multiply parentheses

b^2+300b

Back to the equation:

+(b^2+300b)


We get rid of parentheses

b^2+300b

Back to the equation:

+(b^2+300b)


We get rid of parentheses

b^2+300b+)/300*b=0

We multiply all the terms by the denominator


b^2*300*b+300b*300*b+)=0

We add all the numbers together, and all the variables

b^2*300*b+300b*300*b=0

Wy multiply elements

300b^3*b+90000b^2*b=0

We do not support ebpression: b^3