((3b+4)/4)-((1-4b)/3)=((5b-1)6)

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Solution for ((3b+4)/4)-((1-4b)/3)=((5b-1)6) equation: 



((3b+4)/4)-((1-4b)/3)=((5b-1)6)

We move all terms to the left:

((3b+4)/4)-((1-4b)/3)-(((5b-1)6))=0

We add all the numbers together, and all the variables

((3b+4)/4)-((-4b+1)/3)-(((5b-1)6))=0

We calculate fractions


-(((5b-1)6))+(9b+12)/()+(16b-4)/()=0



We calculate terms in parentheses: -(((5b-1)6)), so:

((5b-1)6)



We calculate terms in parentheses: +((5b-1)6), so:

(5b-1)6

We multiply parentheses

30b-6

Back to the equation:

+(30b-6)



We get rid of parentheses

30b-6

Back to the equation:

-(30b-6)



We get rid of parentheses

-30b+(9b+12)/()+(16b-4)/()+6=0

We multiply all the terms by the denominator


-30b*()+(9b+12)+(16b-4)+6*()=0

We add all the numbers together, and all the variables

-30b*()+(9b+12)+(16b-4)=0

We get rid of parentheses

-30b*()+9b+16b+12-4=0

We add all the numbers together, and all the variables

25b-30b*()+8=0

We move all terms containing b to the left, all other terms to the right

25b-30b*()=-8

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