((3b-3)/7)-((b-2)/7)=-1

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Solution for ((3b-3)/7)-((b-2)/7)=-1 equation: 


b in (-oo:+oo)

(3*b-3)/7-((b-2)/7) = -1 // + 1

(3*b-3)/7-((b-2)/7)+1 = 0

(3*b-3)/7+(-1*(b-2))/7+1 = 0

(3*b-3)/7+(-1*(b-2))/7+(1*7)/7 = 0

3*b-1*(b-2)+1*7-3 = 0

2*b-1+7 = 0

2*b+6 = 0

(2*b+6)/7 = 0

(2*b+6)/7 = 0 // * 7

2*b+6 = 0

2*b+6 = 0 // - 6

2*b = -6 // : 2

b = -6/2

b = -3

b = -3

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