((3f-10)/5)7

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Solution for ((3f-10)/5)7 equation: 


f in (-oo:+oo)

(3*f-10)/5 > 7 // - 7

(3*f-10)/5-7 > 0

(3*f-10)/5+(-7*5)/5 > 0

3*f-7*5-10 > 0

3*f-45 > 0

(3*f-45)/5 > 0

(3*f-45)/5 > 0 // * 5^2

5*(3*f-45) > 0

( 3*f-45 )

3*f-45 > 0 // + 45

3*f > 45 // : 3

f > 45/3

f > 15

( 5 )

5 > 0

f należy do R

	(-oo:15)	(15:+oo)
3*f-45	-	+
5	+	+


f in (15:+oo)

(15:+oo)

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