((3k-7)/2)=2

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Solution for ((3k-7)/2)=2 equation: 


k in (-oo:+oo)

(3*k-7)/2 = 2 // - 2

(3*k-7)/2-2 = 0

(3*k-7)/2+(-2*2)/2 = 0

3*k-2*2-7 = 0

3*k-11 = 0

(3*k-11)/2 = 0

(3*k-11)/2 = 0 // * 2

3*k-11 = 0

3*k-11 = 0 // + 11

3*k = 11 // : 3

k = 11/3

k = 11/3

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