((3m+2)/5m)+((2m-1)/2m)=4

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Solution for ((3m+2)/5m)+((2m-1)/2m)=4 equation: 


m in (-oo:+oo)

m*((3*m+2)/5)+m*((2*m-1)/2) = 4 // - 4

m*((3*m+2)/5)+m*((2*m-1)/2)-4 = 0

(m*(3*m+2))/5+(m*(2*m-1))/2-4 = 0

(2*m*(3*m+2))/(2*5)+(5*m*(2*m-1))/(2*5)+(-4*2*5)/(2*5) = 0

2*m*(3*m+2)+5*m*(2*m-1)-4*2*5 = 0

16*m^2-m-40 = 0

16*m^2-m-40 = 0

16*m^2-m-40 = 0

DELTA = (-1)^2-(-40*4*16)

DELTA = 2561

DELTA > 0

m = (2561^(1/2)+1)/(2*16) or m = (1-2561^(1/2))/(2*16)

m = (2561^(1/2)+1)/32 or m = (1-2561^(1/2))/32

(m-((1-2561^(1/2))/32))*(m-((2561^(1/2)+1)/32)) = 0

((m-((1-2561^(1/2))/32))*(m-((2561^(1/2)+1)/32)))/(2*5) = 0

((m-((1-2561^(1/2))/32))*(m-((2561^(1/2)+1)/32)))/(2*5) = 0 // * 2*5

(m-((1-2561^(1/2))/32))*(m-((2561^(1/2)+1)/32)) = 0

( m-((1-2561^(1/2))/32) )

m-((1-2561^(1/2))/32) = 0 // + (1-2561^(1/2))/32

m = (1-2561^(1/2))/32

( m-((2561^(1/2)+1)/32) )

m-((2561^(1/2)+1)/32) = 0 // + (2561^(1/2)+1)/32

m = (2561^(1/2)+1)/32

m in { (1-2561^(1/2))/32, (2561^(1/2)+1)/32 }

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