((3p+1)/7)+((2p-4)/7)=1

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Solution for ((3p+1)/7)+((2p-4)/7)=1 equation: 


p in (-oo:+oo)

(3*p+1)/7+(2*p-4)/7 = 1 // - 1

(3*p+1)/7+(2*p-4)/7-1 = 0

(3*p+1)/7+(2*p-4)/7+(-1*7)/7 = 0

3*p+2*p-1*7-4+1 = 0

5*p-7-3 = 0

5*p-10 = 0

(5*p-10)/7 = 0

(5*p-10)/7 = 0 // * 7

5*p-10 = 0

5*p-10 = 0 // + 10

5*p = 10 // : 5

p = 10/5

p = 2

p = 2

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