((3x)(2x))+4=28

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Solution for ((3x)(2x))+4=28 equation:


Simplifying
((3x)(2x)) + 4 = 28

Remove parenthesis around (3x)
(3x(2x)) + 4 = 28

Remove parenthesis around (2x)
(3x * 2x) + 4 = 28

Reorder the terms for easier multiplication:
(3 * 2x * x) + 4 = 28

Multiply 3 * 2
(6x * x) + 4 = 28

Multiply x * x
(6x2) + 4 = 28

Reorder the terms:
4 + (6x2) = 28

Solving
4 + (6x2) = 28

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + (6x2) = 28 + -4

Combine like terms: 4 + -4 = 0
0 + (6x2) = 28 + -4
(6x2) = 28 + -4

Combine like terms: 28 + -4 = 24
(6x2) = 24

Divide each side by '6'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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