((3x)-6)+(2x)=78

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Solution for ((3x)-6)+(2x)=78 equation: 



((3x)-6)+(2x)=78

We move all terms to the left:

((3x)-6)+(2x)-(78)=0

We add all the numbers together, and all the variables

2x+(3x-6)-78=0

We get rid of parentheses

2x+3x-6-78=0

We add all the numbers together, and all the variables

5x-84=0

We move all terms containing x to the left, all other terms to the right

5x=84

x=84/5

x=16+4/5

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