((3x)-6)+(2x)=78

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Solution for ((3x)-6)+(2x)=78 equation:



((3x)-6)+(2x)=78
We move all terms to the left:
((3x)-6)+(2x)-(78)=0
We add all the numbers together, and all the variables
2x+(3x-6)-78=0
We get rid of parentheses
2x+3x-6-78=0
We add all the numbers together, and all the variables
5x-84=0
We move all terms containing x to the left, all other terms to the right
5x=84
x=84/5
x=16+4/5

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