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D( x )
6*pi = 0
6*pi = 0
6*pi = 0
6*pi = 0
x belongs to the empty set
x in (-oo:+oo)
(1-x)/3+(3*x)/(6*pi) = 0
(1-x)/3+(pi^-1*x)/2 = 0
(2*(1-x))/(2*3)+(3*pi^-1*x)/(2*3) = 0
2*(1-x)+3*pi^-1*x = 0
(3*pi^-1-2)*x+2 = 0
((3*pi^-1-2)*x+2)/(2*3) = 0
((3*pi^-1-2)*x+2)/(2*3) = 0 // * 2*3
(3*pi^-1-2)*x+2 = 0
(3*pi^-1-2)*x+2 = 0 // - 2
(3*pi^-1-2)*x = -2 // : 3*pi^-1-2
x = -2/(3*pi^-1-2)
x = -2/(3*pi^-1-2)
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