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((3x+1)/3)-((13)/2)=((1-x)/4)
We move all terms to the left:
((3x+1)/3)-((13)/2)-(((1-x)/4))=0
We add all the numbers together, and all the variables
((3x+1)/3)-(((-1x+1)/4))-(+13/2)=0
We get rid of parentheses
((3x+1)/3)-(((-1x+1)/4))-13/2=0
We calculate fractions
(((3x+1)*4))*2)/()+(-(((-1x+1)*3)*2)/()+()/()=0
We calculate terms in parentheses: -(((-1x+1)*3)*2)/(), so:We add all the numbers together, and all the variables
((-1x+1)*3)*2)/(
We multiply all the terms by the denominator
((-1x+1)*3)*2)
We calculate terms in parentheses: +((-1x+1)*3)*2), so:We get rid of parentheses
(-1x+1)*3)*2
We multiply parentheses
-2x+
We add all the numbers together, and all the variables
-2x
Back to the equation:
+(-2x)
-2x
Back to the equation:
-(-2x)
(((3x+1)*4))*2)/()+(-(-2x)+1=0
We get rid of parentheses
(((3x+1)*4))*2)/()+(+2x+1=0
We multiply all the terms by the denominator
(((3x+1)*4))*2)+2x*()+(+1*()+(=0
We add all the numbers together, and all the variables
(((3x+1)*4))*2)+2x*()+(=0
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