((3x+12)/(5x))=((x+4)/(10x))

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Solution for ((3x+12)/(5x))=((x+4)/(10x)) equation:


D( x )

10*x = 0

5*x = 0

10*x = 0

10*x = 0

10*x = 0 // : 10

x = 0

5*x = 0

5*x = 0

5*x = 0 // : 5

x = 0

x in (-oo:0) U (0:+oo)

(3*x+12)/(5*x) = (x+4)/(10*x) // - (x+4)/(10*x)

(3*x+12)/(5*x)-((x+4)/(10*x)) = 0

(3*x+12)/(5*x)+(-1*(x+4))/(10*x) = 0

(10*x*(3*x+12))/(5*10*x*x)+(-1*5*x*(x+4))/(5*10*x*x) = 0

10*x*(3*x+12)-1*5*x*(x+4) = 0

25*x^2+100*x = 0

25*x^2+100*x = 0

25*x*(x+4) = 0

x+4 = 0 // - 4

x = -4

25*x*(x+4) = 0

(25*x*(x+4))/(5*10*x*x) = 0

(25*x*(x+4))/(5*10*x*x) = 0 // * 5*10*x*x

25*x*(x+4) = 0

( 25*x )

25*x = 0 // : 25

x = 0

( x+4 )

x+4 = 0 // - 4

x = -4

x in { 0}

x = -4

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