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((3x+13)/2)+((x-13)/3)=19/2
We move all terms to the left:
((3x+13)/2)+((x-13)/3)-(19/2)=0
We add all the numbers together, and all the variables
((3x+13)/2)+((x-13)/3)-(+19/2)=0
We get rid of parentheses
((3x+13)/2)+((x-13)/3)-19/2=0
We calculate fractions
(9x+39)/()+(((x-13)*2)*2)/()+()/()=0
We calculate terms in parentheses: +(((x-13)*2)*2)/(), so:We add all the numbers together, and all the variables
((x-13)*2)*2)/(
We multiply all the terms by the denominator
((x-13)*2)*2)
We calculate terms in parentheses: +((x-13)*2)*2), so:Back to the equation:
(x-13)*2)*2
We multiply parentheses
2x+
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
+(2x)
2x+(9x+39)/()+1=0
We multiply all the terms by the denominator
2x*()+(9x+39)+1*()=0
We add all the numbers together, and all the variables
2x*()+(9x+39)=0
We get rid of parentheses
2x*()+9x+39=0
We add all the numbers together, and all the variables
9x+2x*()+39=0
We move all terms containing x to the left, all other terms to the right
9x+2x*()=-39
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