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((3x+2))/5=4x
We move all terms to the left:
((3x+2))/5-(4x)=0
We add all the numbers together, and all the variables
-4x+((3x+2))/5=0
We multiply all the terms by the denominator
-4x*5+((3x+2))=0
We calculate terms in parentheses: +((3x+2)), so:Wy multiply elements
(3x+2)
We get rid of parentheses
3x+2
Back to the equation:
+(3x+2)
-20x+(3x+2)=0
We get rid of parentheses
-20x+3x+2=0
We add all the numbers together, and all the variables
-17x+2=0
We move all terms containing x to the left, all other terms to the right
-17x=-2
x=-2/-17
x=2/17
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