((3x+2)/7)-((x+4)/5)=2

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Solution for ((3x+2)/7)-((x+4)/5)=2 equation: 



((3x+2)/7)-((x+4)/5)=2

We move all terms to the left:

((3x+2)/7)-((x+4)/5)-(2)=0

We calculate fractions


(15x+10)/()+(-7x-28)/()-2=0

We multiply all the terms by the denominator


(15x+10)+(-7x-28)-2*()=0

We add all the numbers together, and all the variables

(15x+10)+(-7x-28)=0

We get rid of parentheses

15x-7x+10-28=0

We add all the numbers together, and all the variables

8x-18=0

We move all terms containing x to the left, all other terms to the right

8x=18

x=18/8

x=2+1/4

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