((3x+2x)*2+2x-1)+(2x+3-x)+2x-1=5x+x+(2-3x)-1

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Solution for ((3x+2x)*2+2x-1)+(2x+3-x)+2x-1=5x+x+(2-3x)-1 equation:



((3x+2x)*2+2x-1)+(2x+3-x)+2x-1=5x+x+(2-3x)-1
We move all terms to the left:
((3x+2x)*2+2x-1)+(2x+3-x)+2x-1-(5x+x+(2-3x)-1)=0
We add all the numbers together, and all the variables
((+5x)*2+2x-1)+(x+3)+2x-(5x+x+(-3x+2)-1)-1=0
We add all the numbers together, and all the variables
2x+((+5x)*2+2x-1)+(x+3)-(5x+x+(-3x+2)-1)-1=0
We get rid of parentheses
2x+((+5x)*2+2x-1)+x-(5x+x+(-3x+2)-1)+3-1=0
We calculate terms in parentheses: +((+5x)*2+2x-1), so:
(+5x)*2+2x-1
We add all the numbers together, and all the variables
2x+(+5x)*2-1
We multiply parentheses
2x+10x-1
We add all the numbers together, and all the variables
12x-1
Back to the equation:
+(12x-1)
We calculate terms in parentheses: -(5x+x+(-3x+2)-1), so:
5x+x+(-3x+2)-1
We add all the numbers together, and all the variables
6x+(-3x+2)-1
We get rid of parentheses
6x-3x+2-1
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
We add all the numbers together, and all the variables
3x+(12x-1)-(3x+1)+2=0
We get rid of parentheses
3x+12x-3x-1-1+2=0
We add all the numbers together, and all the variables
12x=0
x=0/12
x=0

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