((3x+3)/(x-3))=5

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Solution for ((3x+3)/(x-3))=5 equation: 



((3x+3)/(x-3))=5

We move all terms to the left:

((3x+3)/(x-3))-(5)=0



Domain of the equation: (x-3))!=0

x∈R



We multiply all the terms by the denominator


((3x+3)-5*(x-3))=0



We calculate terms in parentheses: +((3x+3)-5*(x-3)), so:

(3x+3)-5*(x-3)

We multiply parentheses

(3x+3)-5x+15

We get rid of parentheses

3x-5x+3+15

We add all the numbers together, and all the variables

-2x+18

Back to the equation:

+(-2x+18)



We get rid of parentheses

-2x+18=0

We move all terms containing x to the left, all other terms to the right

-2x=-18

x=-18/-2

x=+9

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