((3x+4)/7x)+5=6/x

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Solution for ((3x+4)/7x)+5=6/x equation: 



((3x+4)/7x)+5=6/x

We move all terms to the left:

((3x+4)/7x)+5-(6/x)=0



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

((3x+4)/7x)-(+6/x)+5=0

We get rid of parentheses

((3x+4)/7x)-6/x+5=0

We calculate fractions


(((3x+4)*x)/7x*x)+(-42x)/7x*x)+5=0



We calculate terms in parentheses: +(((3x+4)*x)/7x*x), so:

((3x+4)*x)/7x*x

We multiply all the terms by the denominator


((3x+4)*x)



We calculate terms in parentheses: +((3x+4)*x), so:

(3x+4)*x

We multiply parentheses

3x^2+4x

Back to the equation:

+(3x^2+4x)



We get rid of parentheses

3x^2+4x

Back to the equation:

+(3x^2+4x)



We get rid of parentheses

3x^2+4x+(-42x)/7x*x)+5=0

We multiply all the terms by the denominator


3x^2*7x*x)+5+4x*7x*x)+5+(-42x)=0

Wy multiply elements

147x^6*x=0

We do not support expression: x^6

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