((3x-1)+(7x+1))1/2=10

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Solution for ((3x-1)+(7x+1))1/2=10 equation: 


x in (-oo:+oo)

((3*x+7*x-1+1)^1)/2 = 10 // - 10

((3*x+7*x-1+1)^1)/2-10 = 0

(3*x+7*x-1+1)/2-10 = 0

(10*x)/2-10 = 0

(10*x)/2+(-10*2)/2 = 0

10*x-10*2 = 0

10*x-20 = 0

(10*x-20)/2 = 0

(10*x-20)/2 = 0 // * 2

10*x-20 = 0

10*x-20 = 0 // + 20

10*x = 20 // : 10

x = 20/10

x = 2

x = 2

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