((3x-1)/x-2)=(3x+6)/x+3

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Solution for ((3x-1)/x-2)=(3x+6)/x+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x-1)/x-2 = (3*x+6)/x+3 // - (3*x+6)/x+3

(3*x-1)/x-((3*x+6)/x)-3-2 = 0

(3*x-1)/x+(-1*(3*x+6))/x-3-2 = 0

(3*x-1)/x+(-1*(3*x+6))/x+(-3*x)/x+(-2*x)/x = 0

3*x-1*(3*x+6)-3*x-2*x-1 = 0

-3*x-2*x-7 = 0

-5*x-7 = 0

(-5*x-7)/x = 0

(-5*x-7)/x = 0 // * x

-5*x-7 = 0

-5*x-7 = 0 // + 7

-5*x = 7 // : -5

x = 7/(-5)

x = -7/5

x = -7/5

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