((3x-12)/(x+4))*(((x/3)+(4/3))/(x-4))

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Solution for ((3x-12)/(x+4))*(((x/3)+(4/3))/(x-4)) equation: 


D( x )

x+4 = 0

x-4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:-4) U (-4:4) U (4:+oo)

((3*x-12)/(x+4))*((x/3+4/3)/(x-4)) = 0

((3*x-12)*(1/3*x+4/3))/((x+4)*(x-4)) = 0

( 1/3*x+4/3 )

1/3*x+4/3 = 0 // - 4/3

1/3*x = -4/3 // : 1/3

x = -4/3/1/3

x = -4

( 3*x-12 )

3*x-12 = 0 // + 12

3*x = 12 // : 3

x = 12/3

x = 4

x in { -4} 

x in { 4} 

x belongs to the empty set

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