((3x-2)/7)+x=((5x+3)/3)

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Solution for ((3x-2)/7)+x=((5x+3)/3) equation: 


x in (-oo:+oo)

(3*x-2)/7+x = (5*x+3)/3 // - (5*x+3)/3

(3*x-2)/7-((5*x+3)/3)+x = 0

(3*x-2)/7+(-1*(5*x+3))/3+x = 0

(3*(3*x-2))/(3*7)+(-1*7*(5*x+3))/(3*7)+(3*7*x)/(3*7) = 0

3*(3*x-2)-1*7*(5*x+3)+3*7*x = 0

21*x-26*x-27 = 0

-5*x-27 = 0

(-5*x-27)/(3*7) = 0

(-5*x-27)/(3*7) = 0 // * 3*7

-5*x-27 = 0

-5*x-27 = 0 // + 27

-5*x = 27 // : -5

x = 27/(-5)

x = -27/5

x = -27/5

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