((3x-4)/7)=5

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Solution for ((3x-4)/7)=5 equation: 



((3x-4)/7)=5

We move all terms to the left:

((3x-4)/7)-(5)=0

We multiply all the terms by the denominator


((3x-4)-5*7)=0



We calculate terms in parentheses: +((3x-4)-5*7), so:

(3x-4)-5*7

We add all the numbers together, and all the variables

(3x-4)-35

We get rid of parentheses

3x-4-35

We add all the numbers together, and all the variables

3x-39

Back to the equation:

+(3x-39)



We get rid of parentheses

3x-39=0

We move all terms containing x to the left, all other terms to the right

3x=39

x=39/3

x=13

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