((3x-6)/3)+9=18

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Solution for ((3x-6)/3)+9=18 equation: 



((3x-6)/3)+9=18

We move all terms to the left:

((3x-6)/3)+9-(18)=0

We add all the numbers together, and all the variables

((3x-6)/3)-9=0

We multiply all the terms by the denominator


((3x-6)-9*3)=0



We calculate terms in parentheses: +((3x-6)-9*3), so:

(3x-6)-9*3

We add all the numbers together, and all the variables

(3x-6)-27

We get rid of parentheses

3x-6-27

We add all the numbers together, and all the variables

3x-33

Back to the equation:

+(3x-33)



We get rid of parentheses

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11

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